For which values of x is the inequality 3(1 + x) < x + 6 true?

a) 0 & 1
b) 2 & 3
c) 4 & 5
d) 6 & 7

A

Step-by-step explanation:

The values which make an inequality true are the solutions to the inequality found using inverse operations.

3(1 + x) < x + 6

3 + 3x < x + 6

3 + 2x < 6

2x < 3

x < 3/2

3/2 is the value 1.5 so x must be less than 1.5. Only 0 and 1 make it true in the options given.

dd

step-by-step explanation:

dd