Water tank a has a capacity of 550 gallons and is 66% full. water tank b is 53% full. the ratio of the capacity of the tank a to tank b is 11: 15. how much water is in tank a? what is the capacity of the tank b? how much water is in the tank b?

Capacity of Tank B = 750 gal

363 gal in Tank A and 397.5 gal in Tank B

Step-by-step explanation:

(a) Volume of Tank B

V_A = 550 gal

V_A/V_B = 11/15

550/V_B = 11/15

Multiply each side by 15    (15 × 550)/V_B = 11

Multiply each side by V_B           5 × 550 = 11V_B

Divide each side by 11                 15 ×   50 =      V_B

                                                           V_B = 750 gal

The capacity of Tank B is 750 gal.

(b) Water in each tank

In Tank A: 550 × 0.66 = 363   gal

In Tank B: 750 × 0.53 = 397.5 gal

There are 363 gal in Tank A and 397.5 gal in Tank B.

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.