What are the vertex and x-intercepts of the graph of y=x^2-2x-24

Vertex : (1,-25) ; x intercepts : (6,0)&(-4,0)

Step-by-step explanation:

adding 25 on both sides

let us convert the above equation in the standard form

let y+25=Y

    x-1=X

vertex of above equation is (0,0)

replacing them into original form is x-1=0 , x=1

y+25=0 ; y=-25

Hence the vertex is (1,-25)

Part 2 :

In order to find the x intercepts , we put y=0 and solve for x

taking square roots on both sides we get

±5=x-1

solving   get x=±5+1 ; x=5+1=6 ; x=-5+1=-4

Hence y intercepts are (-4,0) & (6,0)

what is the question here

step-by-step explanation: