At the coffee shop, two coffees and one latte cost $10.50. three coffees and two lattes cost $17.00. what is the cost of one coffee?
a. $4.00
b. $6.50
c. $5.25
me !

To solve this problem, we can set two equations.

Let x be the cost of coffee and y be the cost of latte.

Two coffees and one latte: 2x + y = 10.50

y=10.50 - 2x ...(1)

Three coffees and two lattes: 3x + 2y = 17.00...(2)

Put (1) into (2), we have:

3x + 2(10.50-2x) = 17.00

3x + 2(10.50) - 2(2x) = 17.00

3x + 21 - 4x = 17

Put the unknown to one side:

3x -4x = 17 - 21

-x = -4

When there are negative numbers on both sides, we can take the negative signs away:

x= 4

Therefore, cost of one coffee is A. $4.00.

Hope ot helps!

the answer is d

step-by-step explanation:

1.3 million hoops i believe