Given △abc,
ad and be are medians, ad ∩be=g.
prove: gd/ag = de/ab

See explanantion

Step-by-step explanation:

Since AD and BE are medians, then points D and E are midpoints of the sides BC and AC, respectively. Thus, segment DE is triangle's midline. By the Triangle midline theorem, DE is parallel to the side AB. Thus,

as alternate interior angles.

Moreover, as vertical angles.

This gives us that triangles ABG and DEG are similar by AAA postulate.

Hence,

ab will be equal to