Find three consecutive odd numbers the product of which is 148 more than the cube of their middle number.

   The numbers are

Step-by-step explanation:

Let

x-----> the first odd number

x+2----> the middle odd number

x+4---> the third odd number

The numbers are

4th option is correct xy=-10

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hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~