What is the vertex of the quadratic function fix=(x-8)(x-2)

Vertex: (5, -9)

Step-by-step explanation:

fix = (x-8)(x-2)

fix = x^2 - 2x - 8x + 16

fix = x^2 - 10x + 16

a = 1, b = -10, and c = 16

To find vertex:

x = -b/2a

x = -(-10)/2(1)

x = 10/2

x = 5

y = 5^2 - 10(5) + 16

y = 25 -50 + 16

y = -9

Vertex: (5, -9)

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363

hi there!

question 1 answer: p/q can be terminating when q = 5^m * 2^n

question 2 answer: -1 and -1

question 3 answer: -4

question 4 answer: 5/12

hope this : )