The length of a new rectangular playing field is 8 yards longer than double the width. if the perimeter of the rectangular playing field is 280 yards, what are its dimensions.

Let

width,w

length, l = 2w +8...eqn 1

perimeter, p = 2 (l + w)...eqn 2

subst for l in eqn 2...

p = 2(2w +8 + w) = 2 (3w + 8) = 280

280 = 6w + 16

w = 264 /6 = 44

subst for w in eqn 1

l = 2× 44 + 8 = 96

length = 96yds

width = 44 yds

exa:

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3+11

14

step-by-step explanation:

from this example, we can see that subtracting with integers is the same as adding the opposite. we can solve using a number line or by using the saying "keep, change, change" to us solve. it is important to remember that we can subtract a negative and end up with a larger number than we started with.

idk

step-by-step explanation:

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