Question 2 (1 point)

what is an equation of the line that is perpendicular to y=3x−9

and that passes through the point (3, 1) ?
question 2 options:

y=3x+2

y=−13x+2

y=13x+2

y=-3x+2
question 3 (1 point)

select the following lines that would be perpendicular to y = 3x + 1. (select all correct)
question 3 options:

the line passing through points (3,8) and (6,9).

the line passing through points (1,4) and (4,3).

the line passing through points (1,-4) and (4,-5).

the line passing through points (4,3) and (5,6).

➷ Perpendicular ==> negative reciprocal slope

1 = (-1/3)(3) + c

1 = -1 + c

c = 2

It would be y = -1/3x + 2

Q3) slope = difference in y / difference in x

Eq 1 slope: 1/3

Eq 2 slope: -1/3

Eq 3 slope: 1/3

Eq 4 slope: 3/1

It would be The line passing through points (1,4) and (4.3)

A line is perpendicular if it has the negative reciprocal slope

➶ Hope This Helps You!

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solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.