Y= 4x - 6
2x - 3y = 8

if this problem is to be solved by substitution, which is a correct step?
a) 2x - 12x + 18 = 8
b) 2x - 12x - 18 = 8
c) 2x - 4x + 6 = 8
d) 2x + 12x + 18 = 8

A

Step-by-step explanation:

Given the 2 equations

y = 4x - 6 → (1)

2x - 3y = 8 → (2)

Substitute y = 4x - 6 into (2)

2x - 3(4x - 6) = 8 ← distribute and simplify left side

2x - 12x + 18 = 8 → A

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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