Earl paid $37.95 for admission to the amusement park. each ride costs and additional $4.25. earl only has $75. what is the maximum number of rides he can go on?

8

Step-by-step explanation:

1. Determine how much Earl has to spend on rides. Subtract the admission (37.95) from his starting number (75)

       75.00-37.95 = 36.05

2. Divide 36.05 by the cost per ride (4.25)

    36.05/4.25 = 8.48

Since Earl cannot ride part of a ride (.48) he can only ride 8 rides.

8 rides is the maximum

Step-by-step explanation:

The equation is 37.95+x(4.25)≥75

x is the number of rides

Start by taking away the admission cost from the total amount he has

75-37.95=37.05

Now we know each ride costs 4.25 extra

so divide 37.05 by 4.25

you get 8.7176...

the whole number in there is 8

he can go on a maximum of 8 rides.

check your answer by plugging the numbers into the equation

37.95+8(4.25)≥75

37.95+34≥75

71.95≥75

Just to make sure he can't go on any more rides subtract 71.95 from 75

75-71.95=3.05

no he cannot go on anymore rides

figure c

step-by-step explanation:

hope this .

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w