The circle below is centered at the point (4, 1) and has a radius of length 2 what is its equation?

(x - 4)^2 + (y - 1)^2 = 2^2 = 4

Step-by-step explanation:

The applicable equation of a circle with center at (h, k) and radius r is

(x - h)^2 + (y - k)^2 = r^2.  Here, h = 4; k = 1; and r = 2.

So the desired equation is (x - 4)^2 + (y - 1)^2 = 2^2

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation:

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)