Assume that a company hires employees on mondays, tuesdays, or wednesdays with equal likelihood. a. if two different employees are randomly selected, what is the probability that they were both hired on a monday? b. if two different employees are randomly selected, what is the probability that they were both hired on the same day of the week? c. what is the probability that 7 people in the same department were all hired on the same day of the week? d. is such an event unlikely?

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

.

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is . We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

So

.

C. If the probability that two people have been hired on a specific day of the week is , then the probability that 7 people have been hired on the same day is:

D. The probability is . This number is quite close to zero. Therefore it is an unlikely bastate event.

choose (5, 1.5) and (-1.5,-3.5)

step-by-step explanation:

5 - 1.5 =3.5

-1.5 - (-3.5) = 2

3.5 + 2 =5.5

hope this !

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step-by-step explanation:

this is a parabola.