Apoint moves in the plane in the following sequence. a point moves down 2 units, reflects over the x-axis, moves right 4 units, and then reflects over the y-axis. which of the following points follows the sequence and has the same starting and ending point?

a.(2, 3)
b.(–1, 1)
c.(–3, –3)
d.(–2, 1)

D

Step-by-step explanation:

The answer is point D(-2,1).

1. If the point D was moved down 2 units, then its coordinates became (-2,-1).

2. If point (-2,-1) was reflected over the x-axis, then its coordinates became (-2,1).

3. If the point (-2,1) was moved 4 units to the right, then its coordinates became (2,1).

4. If point (2,1) was reflected over y-axis, its coordinates became (-2,1).

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).

answer: im sorry i dont get it

step-by-step explanation: