Gianna invested $47,000 in an account paying an interest rate of 6.9% compounded monthly. assuming no deposits or withdrawals are made, how much money, to the nearest hundred dollars, would be in the account after 19 years?

Using the equation A=P(1+(r/n))^nt.

n=monthly, so it's 12.

t=19 years

r=6.9% as a decimal is .069

P=47,000

.069/12=.00575

.00575+1=1.00575

nt=12*19=228

1.00575^228=3.695

3.695*47000=$173,711

$173,711

no one knows lol

step-by-step explanation:

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form