Asap! find the area of quadrilateral abcd in each case.

The area is 5 units²

Step-by-step explanation:

∵ The area of the square of side length 3 which contains

   the quadrilateral ABCD = 3 × 3 = 9 units²

∵ The area of the 4 triangles on the sides of the quadrilateral ABCD

   = 1/2(2)(1) + 1/2(1)(2) + 1/2(2)(1) + 1/2(1)(2) = 4 units²

∴ The area of quadrilateral ABCD = 9 - 4 = 5 units²

answer: 94

step-by-step explanation: 79+91+92+94+94 = 450 divided by 5 (since there are 5 number that are being added) = 90

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