Best answer will be
compute the number of three-digit integers (from 100 to 999 inclusive) that have at least one digit that is a 4.

252

Step-by-step explanation:

The number of integers from 100 to 999 is 999 - 100 +1 = 900.

Consider the number of three-digit integers that do not contain 4 as a digit.

For the hundreds digit, there are 8 possible choices (excluding 0 and 4).

For the tens digit, there are 9 possible choices (excluding 4).

For the ones digit, there are 9 possible choices (excluding 4)

Thus, there are 8 × 9 × 9 = 648 three-digit integers without a 4.

The number of three-digit integers with at least one 4 is 900 - 648 = 252.

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.