What is the solution to the system of equations? use any method. {3x+y=32x+y=7 {2x+y=7

x = 12  and  y = 1

Explanation:

Given equations are:

(1)  1 3 x − y = 3

(2) 2 x + y = 25

Multiply (1) by 3 to eliminate the fractional part,

(1)  x − 3 y = 9  ⇒ x = 9 + 3 y

let this be equation (3)

Now substitute this value of  

x

from (3) in equation (2),

(2)  2 ( 9 + 3 y ) + y = 25  ⇒ 18 + 6 y + y = 25  ⇒ 7 y = 25 − 18  ⇒ y = 7 7

Therefore,

y = 1

Substituting this value of  

y

in equation (3),

x = 9 + 3 × 1  

x = 9 + 3

Therefore,

x = 12

So we have the values of  

x  and  y  as,

x = 12

and  

y = 1

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∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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