Im really stuck on this can someone

a jet aircraft travels 1416 miles from atlanta to el paso. traveling against the wind, the trip
takes 3.2 hours. the return trip with the wind takes 2.4 hours. find the speed of the aircraft in
still air and the speed of the wind.

Step-by-step explanation:

The equations are

u - v = 1416%2F3.2     (1)   (effective speed flying against the wind)

u + v = 1416%2F2.4     (2)   (effective speed flying with the wind)

where "u" is the aircraft speed at no wind and "v" is the speed of wind.

Simplify (1) and (2):

u - v = 442.5    (3)

u + v = 590.     (4)

Add equations (3) and (4). You will get

2u = 1032.5  >  u = 1032.5%2F2 = 516.25.

Thus we found the speed of the aircraft at no wind. It is 516.25 mph.

Now from equation (4)  v = 590 - 516.25 = 73.75 mph.

Answer.  the speed of the aircraft at no wind is 516.25 mph.  The speed of wind is 73.75 mph.

Solved.  

It is a typical "tailwind and headwind" word problem.  

5050

hope this !

(-5,-28)

i graphed to on desmos.