The position function of a particle in rectilinear motion is given by s(t) = t3 – 12t2 + 45t + 4 for t ≥ 0 with t measured in seconds and s(t) measured in feet. find the position and acceleration of the particle at the instant when the particle reverses direction. include units in your answer.

With position function

the velocity of the particle is given by

The particle changes direction when its velocity changes sign. We have

so the particle's direction is reversed at two different times.

The acceleration is given by

When , the particle's position is ft and its acceleration is ft/s^2.

When , the particle's position is ft and its acceleration is ft/s^2.

a is the right answer

0.0076, if you meant 4.125 divided by 0.03125 it would be 132

step-by-step explanation:

first you have to move the decimal in 0.03125 over until its behind the 5 which is 5 places over. now the number is 3125

then you have to move the decimal in 4.125, 5 places over. now the number is 4,112,500.

now you divide like you would normally would and get 0.0076