Let f(x)=x^2+10x+29 .

what is the minimum value of the function?

enter your answer in the box.

4

Step-by-step explanation:

given

f(x) = x² + 10x + 29

Since the coefficient of the x² term > 0, f(x) will have a minimum value

Use the method of completing the square

add/ subtract ( half the coefficient of the x- term )² to x² + 10x

f(x) = x² + 2(+ 5)x + (5)² - (5)² + 29

    = (x + 5)² - 25 + 29

   = (x + 5)² + 4

When x = - 5 , f(x) has a minimum value at + 4

what? ?

what type of question is thiss

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?