Replace ∗ with a monomial so that the result is an identity:
1. (2a+*)(2a-*)=4a^2-b^2
2. (5x+*)(5x-*)=25x^2-0.16y^4
3. (*-b^4)(b^4+*)=121a^10-b^8
4. (*-3x)(*+3x)=16y^2-9x^2
5. 100m^4-4n^6=(10m^2-*)(*+10m^2)
6. m^4–225c^10 = (m^2 − *)(* +m^2)

QUESTION 1

Taking the right hand side we have;

We can rewrite this as;

We apply difference of two squares.

QUESTION 2

Taking the right hand side we have;

We can rewrite this as;

We apply difference of two squares.

QUESTION 3

Taking the right hand side of the given equation, we have;

We rewrite this as;

QUESTION 4

From the RHS;

This implies that;

QUESTION 5

From the left hand side, we have

This implies that;

Using difference of two squares, we have;

QUESTION 6

From the LHS;

We rewrite to obtain;

Using difference of two squares, we obtain;

2 over 5 and 4 over 15

don’t know last one sorry

step-by-step explanation:

that one look

step-by-step explanation: