Find the vertex and the y-intercept of the graph of y = 2x^2 + 16x + 33.

see explanation

Step-by-step explanation:

Given a quadratic in standard form : ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex is

= -

y = 2x² + 16x + 33 ← is in standard form

with a = 2, b = 16, c = 33, hence

= - = - 4

Substitute x = - 4 into the equation for y- coordinate of vertex

y = 2(- 4)² + 16(- 4) + 33 = 32 - 64 + 33 = 1

vertex = (- 4, 1 )

To find the y- intercept substitute x = 0 into the equation

y- intercept = 2(0)² + 16(0) + 33 = 0 + 0 + 33 = 33

hello 0xxbadwolfxx0,

2.6 x 10^9 is 2,600,000,000.

1.3 x 10^2 is 130

multiplying 130 and 2,600,000,000 would simply give you 200,000,000,000.

therefore, the answer would be d. 2.0 × 10^11.

i hope i ! warm regards, mae.