Solve (x + 2 < 5) ∩ (x - 7 > -6).

1. {x | 1 < x < 3}
2. {x | x < 3 or x > 1}
3. {all real numbers}

1. {x | 1 < x < 3}

Step-by-step explanation:

x + 2 < 5           subtract 2 from both sides

x + 2 - 2 < 5 - 2

x < 3

x - 7 > -6        add 7 to both sides

x > 1

From x < 3 and x > 1 we have 1 < x < 3

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