Two pools are fill with water. to start the first pool contains 1210 l of water and the second pool is empty water is been added to the first pool at a rate of 15.5 l per minute water is being added to the second pool at a rate of 45.75 l per minute

after how many minutes will the two pools have the same amount of water?

how much water will be in each pool when they have the same amount?

40 minutes, 1830 litres

Step-by-step explanation:

1210+15.5t=45.75t

1210=30.25t

1210/30.25=t

40=t

W=45.75t

W=45.75(40)

W=1830L

d

step-by-step explanation:

by observation, we can see that the the graph is simply the graph of y = |x| that has been shifted 4 units downwards and 3 units to the left.

we can recognize in choice d :

y = | x + 3 |   - 4 (rewriting in general form)

y = | x - (- 3) |   - 4

the "-4 " term means   that the graph has been shifted by 4 units in the negative y direction

the "-3 " term means   that the graph has been shifted by 3 units in the negative x direction

this matches our observation of the graph described above.