With math. ill give points, and friend.

use the figure below to answer the question that follows:
intersecting triangles ace and bdf. they intersect at points g, h, i, and j.
what must be given to prove that δcjg ~ δcea?

∠BIJ ≅ ∠CGJ and ∠BJI ≅ ∠CJG

Step-by-step explanation:

We have that the initial triangles are equal. Let us check which components remain within the final triangles as the same. The only such components are the angles B and C. We now know that we have to apply a triangle equality criterion.

The triangles BGH and CIH are equal since the have 2 common sides and the respective interior angles are equal. Then we have that BI=GC and also that the respective angles  B and C are equal. THen also HIJ=HGJ since they fill to 180 degrees with angles that are equal.

Hence by angle-side-angle the triangles BJI and CJG are equal.

∠BIJ ≅ ∠CGJ and ∠BJI ≅ ∠CJG

answer: the distance

step-by-step explanation:

to calculate the distance d of a line segment with endpoints (x1, y1) and (x2, y2) use the formula d (x2 x1)2 (y2 y1)2. to calculate the midpoint of a line segment with endpoints (x1, y1) and (x2, y2) use the formula

i dont get the question

step-by-step explanation: