Find the exact value of sine, cosine, and tangent of a and t for each triangle.

See below  

Step-by-step explanation:

14)

 14² =   8² + TV²

196 = 64  + TV²

TV² = 132

TV =√132 = √(4 × 33) = 2√33

sinA = TV/AT   = (2√33)/14 = √33/7

cosA = AV /AT = 8/14          = 2/7

tanA = TV/AV   = (2√33)/8  = √33)/4

sinT = AV/AT   = 8/14          = 4/7

cosT = TV/AT   = (2√33)/14 = √33/7

tanT = AV/TV   = 8/(2√33)   = (4√33)/33

16)

  6² = 3² + GT²

 36 = 9   + GT ²

GT² = 27

GT  = √27 = √(9 × 3) = 3√3

sinA = GT/AT  = (3√3)/6 = √3/2

cosA = AG/AT = 3/6        = ½

tanA = GT/AG = (3√3)/3 = √3

sinT = AG/AT = 3/6        = ½

cosT = GT/AT = (3√3)/6 = √3/2

tanT = AG/GT = 6/(3√3) = (2√3)/3

18)

 13² =   8² + TX²

169 = 64  + TX²

TX² = 105

TX  = √105

sinA = TX/AT  = (√105)/13

cosA = AX/AT = 8/13

tanA = TX/AX  = (√105)/8

sinT = AX/AT  = 8/13

cosT = TX/AT  = (√105)/13

tanT = AX/TX  = 8/(√105) = (8√105)/105

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.

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