2cars started to move at the same time, at the same direction but one was moving twice as fast as the other. 6 hours later, the 2 cars were 204 miles apart. find the speed for each car.

The speeds are 34 mph for the slower car and 68 mph for the faster car.

Step-by-step explanation:

speed = distance/time

Using s for speed, d for distance, and t for time, we have the equation for speed:

s = d/t

Solve for distance, d, by multiplying both sides by t.

d = st

Now we use the given information.

Speed of slower car: s

Speed of faster car: 2s

Distance traveled by faster car: d

Distance traveled by slower car: d - 204

time traveled by faster car = time traveled by slower car = 6

Distance equation for faster car:

d = st

d = 2s * 6

d = 12s     < equation 1

Distance equation for slower car:

d = st

d - 204 = s * 6

d - 204 = 6s

d = 6s + 204    < equation 2

Now, using equations 1 and 2, we have a system of two equations in two unknowns.

d = 12s

d = 6s + 204

Since the first equation is already solved for d, we can use the substitution method. Substitute 12s for d in the second equation:

12s = 6s + 204

6s = 204

s = 34

The speed of the slower car is 34 mph.

The speed of the faster car is

2s = 2(34) = 68

The speed of the faster care is 68 mph.

answer: c. is your answer

step-by-step explanation: get me a black leather coat

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: