Yasmin has a bag containing 165 colored beads. her classmates take turns selecting one bead from the bag without looking, recording the color in the table, and replacing the bead. based on the table, about how many beads of each color are in yasmin’s bag? enter your answers in the boxes. color red brown orange yellow number of beads 10 15 17 13 red, brown, orange, yellow

30 , 45 , 51 , 39

Step-by-step explanation:

You just add up the numbers until you get 165

Number of beads of each color in Yasmin's bag is:

  Red--   30

  Brown--  45

 Orange-- 51

Yellow--  39

The record of experiment are as follows:

Color                    Red            Brown       Orange  Yellow

Number of Beads     10           15              17      13

Total number of beads recorded=10+15+17+13=55 beads

Also, the Probability of Red bead is=10/55

Probability of Brown bead is=15/55

Probability of Orange bead is=17/55

Probability of Yellow bead is=13/55

Number of red beads in Yasmin's bag are:

Number of brown beads in Yasmin's bag are:

Number of orange beads in Yasmin's bag are:

Number of yellow beads in Yasmin's bag are:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

answer: c

because if you look at the chart you can see a pattern and compare it to the question he simplify out your

but i think the formula is f(x)=6x