What is the additive inverse of the complex number 13-2

-13 + j*2

Step-by-step explanation:

The additive inverse of a complex number x = a +j*b

is a number y, such that

x + y = 0

This means that

y = -x = - a - j*b

Therefore

The additive inverse of 13 - j*2 is equal to

-(13 - j*2) = -13 +j*2

welll its a very hard question but ill

step-by-step explanation:

first you take the 6 dollars and add 10 to it then add the 50 to that then multiply by 8 with xy and your answer will be

hope this

1.30

step-by-step explanation: