In this figure, abc is circumscribed about oq. find the perimeter of abc.
answer options: 66, 58, 54, 62

Theorem :If from one external point, two tangents are drawn to a circle then they have equal tangent segments.

Two tangents DB and BE are drawn to a circle from one point i.e.B

So, Using theorem

DB=BE =10 cm

So, Using theorem  

CF = CE = 15 cm

So, using theorem

AD =FA = 8 cm

Now AC = FA+CF = 8+15=23 cm

CB =BE+EC = 10+15=25 cm

AB = AD+DB=8+10=18 cm

Perimeter of triangle = Sum of all sides  

                                     =AB +CB+AC

                                     = 18 + 25 +23

                                     = 56 cm

Hence the perimeter of ΔACB is 56 cm

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.