Apair of linear equations is shown below:

y = −2x + 3
y = −4x − 1

which of the following statements best explains the steps to solve the pair of equations graphically?

a. graph the first equation, which has slope = 3 and y-intercept = −2, graph the second equation, which has slope = −1 and y-intercept = −4, and find the point of intersection of the two lines.
b. graph the first equation, which has slope = −3 and y-intercept = 2, graph the second equation, which has slope = 1 and y-intercept = 4, and find the point of intersection of the two lines.
c. graph the first equation, which has slope = −2 and y-intercept = 3, graph the second equation, which has slope = −4 and y-intercept = −1, and find the point of intersection of the two lines.
d. graph the first equation, which has slope = 2 and y-intercept = −3, graph the second equation, which has slope = 4 and y-intercept = 1, and find the point of intersection of the two lines.

C. Graph the first equation, which has slope = −2 and y-intercept = 3, graph the second equation, which has slope = −4 and y-intercept = −1, and find the point of intersection of the two lines.

Step-by-step explanation:

The two equations are in slope intercept form which is y = mx + b where m is the slope and b is the y-intercept.

In the first equation (y = -2x + 3), -2 is the slope since it is the coefficient. "b" is 3 since it is the constant of the equation.

In the second equation (y = -4x -1), -4 is the slope is the coefficient, and the y-intercept is -1 since it is the constant.

To solve the equations graphically, graph them and find the point where they intersect.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this