Which of the following graphs is a polynomial function with x-intercepts of (-2, 0), (0, 0), and (3, 0)?

The intercepts of the third degree polynomial corresponds to the zeros of the equation

y = d*(x-a)*(x-b)(x-c)

Where a, b and c are the roots of the polynomial and d an adjustment coefficient.

y = d*(x+2)*(x)*(x-3)

Lets assume d = 1, and we get

y = (x+2)*(x)*(x-3) = x^3 - x^2 - 6x

We graph the equation in the attached file.

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.

equal to

step-by-step explanation: