given the following: med=mdb=mbc

in circle f, what is the measure of efd?

a. 17.5°

b. 35°

c. 60°

d. 70°

Option D.

Step-by-step explanation:

To solve this exercise you must keep on mind the Angle at the Center Theorem.

According to the  Angle at the Center Theorem, an inscribed angle is half of the central angle.

Therefore, given in the inscribed angle m∠BAC=35°, you can calculate the central angle m∠EFD as following:

- Solve for EFD.

- When you substitute values. you obtain:

Option B. ∠EFD = 35°

Step-by-step explanation:

In a circle F, it has been given mED = mDB = mBC

We have to find the measure of ∠EFD

We should always remember the inscribed angle theorem which states that the measure of an inscribed angle is always half the measure of intercepted arc.

m(arc BC) = 2×∠CAB = 2×35 = 70°

Now it has been given in the question

mED = mBC

Therefore m(arc ED) = 70°

Again applying the same theorem

m(arc ED) = 2×∠EFD

70° = 2×∠EFD

m∠EFD =

Option B. 35° is the answer.

6. 104

7. 52/37

8. 2704

9. 140608

10. -52

11. |52|=52

12. 1/52

13. 156

14. 26

15. 40

16. 37

17. -364

18. 53 1/3

19. 50.96

20. 43 2/3

21. 78

22. 50.75

23. 47.63

24. 163.28

25. 10400

26. 338

27. 208

28. 2704 square inches

29. 312 square meters

30. don't know what its asking, tell me so i can tell you

31. 8490.56

32. 52 degrees would be an acute angle

33. 128 degrees

34. 20.8

35. 39

36. 208