2. the geo air pilot is looking at scca from the plane. from the aircraft the angle of depression is 17 degrees. if the plane is at an altitude of 10,000 feet, approximately how far is the plane to scca? round your answer to the nearest tenth. the image is not drawn to scale. (2 points)

The distance  from the plane to SCCA is 34,203.0 feet approximately,  and the horizontal distance is 32,708.5 feet approximately.

Step-by-step explanation:

You can draw a right triangle like the one shown in the figure attached, where:

x: horizontal distance.

y: distance from the plane to SCCA.

You can calculate x as following:

Where:

Substitute and solve for x:

You can calculate y as following:

Where:

Substitute and solve for y:

a.   since the profit made in 2012 is equal to the profit made in 2014, the profit is symmetric about the line y = 120,000.

step-by-step explanation:

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12