What is the standard form of the equation for this circle?
a. -(x – 1)2 – (y + 10)2 + 4 = 0
b. (x – 1)2 – (y + 10)2 = 2
c. (x + 1)2 + (y – 10)2 = 4
d. (x – 1)2 – (y + 10)2 = 4

a (-1, 10)
radius 2

(40 points) i need some . an answer definition is appreciated as well.

Rectangle pqrs has length a and width 4b. the x-axis bisects ps and qr what are the coordinates of the vertices

Consider this equation. |y + 6| = 2 what can be concluded of the equation? check all that apply. there will be one solution. there will be two solutions. the solution to –(y + 6) = 2 will be also be a solution to the given absolute value equation. the solution(s) will be the number(s) on the number line 2 units away from –6. the value of y must be positive since the variable is inside absolute value signs.