What are the x and y intercepts of y=x^2+3x-10 (show all steps )

X-int: (2,0) , (-5,0)

Y-int: (0,-10)

Step-by-step explanation:

To solve for the x-int, set y to 0.

0= x^2 + 3x - 10

0= (x-2)(x+5)

x= 2, and -5

To solve for the y-int, set x to 0.

y= (0)^2 + 3(0) - 10

y= -10

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i ran through it by the other answer is wrong

c and d is your answers.

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