1. what is the solution for n^2-49=0 (1 point)
a) -7
b)7
c) ± 7
d) no solution

2. what is the solution of x^2+64=0 (1 point)
a) -5
b) 8
c) ±8
d) no solution

3. what is the side length of a square with an area of 144x^2 (1 point)
a) 12
b) 12x
c) ±12x
d) no solution

4. what is the value of b in the triangle shown below (1 point) (picture above)
a) -4in
b) 4 in
c) ±4in
d) no solution

5. what is the value of z so that -9 and 9 are both solutions of 103? (1 point)
a) -22
b)3
c)22
d)184

1. Add 49 to both sides, then square root both sides
N=square root of 49
N=plus or minus 7
Because both -7 squared and 7 squared equal 49

2. Subtract 64, then square root
X=square root of -64
Which is actually plus or minus 8i, but I'm assuming your teacher wants you to say no solution

3. Area of square=side length squared
144x^2=s^2
Square root both sides
Assuming 144x^2 means (144)(x^2), which is unusual and should have been specified with parentheses in the question but is the only thing that would make the answer be one of the given answers, you would need to square root both x^2 and 144 separately.
(Plus or minus 12)(x)=s

4. Area of triangle=0.5 base times height
Base=b
24=(0.5)(b)(3b)
24=(0.5)(3b^2)
48=3(b^2)
Square root of 48=square Root of 3(b)
Square root 48/square root 3=b
Plus or minus 4=b

5. This question doesn't make sense

Your pictures are upside down