The calibration of a scale is to be checked by weighing a 10-kg test specimen 25 times. suppose that the results of different weighings are independent of one another and that the weight on each trial is normally distributed with σ = .200 kg. let µ denote the true average weight reading on the scale. (a) what hypotheses should be tested? (b) with the sample mean itself as the test statistic, what is the p-value when x = 9.85, and what would you conclude at significance level .01? (c) for a test with α = .01, what is the probability that recalibration is judged unnecessary when in fact µ = 10.2?

a:  That the mean weight of the trials is 10 kg

b:  See attached photo for work

Step-by-step explanation:

We want to see if the scale is weighing properly and are using a 10 kg weight to calibrate it.  That means our hypothesis test is that the mean weight of the trails (in this case 25) is 10 kg.

The hypothesis we will use are

H0:  µ = 10

Ha:  µ ≠ 10

The alternate hypothesis has a not equals to sign because if the scale weighs too much or to little, then it needs to be better calibrated, so it's a two tailed test.

the formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. if a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %