Is my graph correct?

and what is the range of the function above?

Graph is incorrect.

Find points (x,y)

If x=#, what does y=?

Example:

Y=5x+4

Y=5•0+4

Y=0+4

Y=4

Points:

(0,4)

(-1,1)

(-2,-6)

Also, only draw the line in areas where x≤0

Meaning nothing should be on the right half of the square.

The range means what Y values are possible?

When draw properly, with nothing on the right half, the highest Y value will be 4.

So, the range is y≤4

The range is  f(x) <= 4.

Step-by-step explanation:

The general form of a straight line is y = mx + c where m = the slope of the line and c = the y-intercept. If we compare this with y = 5x + 4 we see that the slope = 5 and the y-intercept is 4.

Your graph has got the wrong slope . The slope should be the coefficient of x which is 5. The slope of your graph ( rise / run) = 1. The y-intercept is +4 which you have correct.

Also since the domain is x <= 0 the line should stop

at the point (0, 4)  because the maximum value of y  is 4.

answer: i'm not going to give you the answer, but some hints to work it out.

step-by-step explanation: so, if there is a straight line that means that the line angle is 180°. so we subtract the 2 angle measures provided, (15 and 38) from 180. so the answer is 180 - (38 + 15). (you have to solve the equation)

1) is right

step-by-step explanation: