Mathematics, 31.01.2020 20:50 lillygrl100

Compute the value of the following expressions: 323 mod 5 323 div 5 −323 mod 5 −323 div 5 327 mod 3 (64 · (−67) + 201) mod 7 (〖38〗^12) mod 6 (〖38〗^12) mod 3

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Answer from: Cookie320

323 mod 5 = 3

−323 mod 5 = -3

327 mod 3 = 0

(64 * (-67) + 201) mod 7 = 6

(38^12) mod 6 = 4

(38^12) mod 3 = 1

Step-by-step explanation:

The modulo operation looks for remainders from the quotients. In order to find them, divide the whole number by the mod number. Then take just the decimal after the whole answer and multiply it by the mod number.

323 mod 5

323/5 = 64.6

.6 * 5 = 3

−323 mod 5

323/5 = -64.6

-.6 * 5 = -3

327 mod 3

327/5 = 109

0 * 3 = 0

(64 * (-67) + 201) mod 7

64 * -67 = -4288 + 201 = 4087

4087/7 = 583.85714

.85714 * 7 = 6

(38^12) mod 6

38^12 = 9.07x10^18

9.07x10^18/6 = 1510956318082499242.6666667

.666667 * 6 = 4

(38^12) mod 3

38^12 = 9.07x10^18

9.07x10^18/3 = 3021912636164998485.333333

.3333333 * 3 = 1

Answer from: jenn8214p3e8mx

323 mod 5 = 3

−323 mod 5 = -3

327 mod 3 = 0

(64 * (-67) + 201) mod 7 = 6

(38^12) mod 6 = 4

(38^12) mod 3 = 1

Step-by-step explanation:

323 mod 5

323/5 = 64.6

.6 * 5 = 3

−323 mod 5

323/5 = -64.6

-.6 * 5 = -3

327 mod 3

327/5 = 109

0 * 3 = 0

(64 * (-67) + 201) mod 7

64 * -67 = -4288 + 201 = 4087

4087/7 = 583.85714

.85714 * 7 = 6

(38^12) mod 6

38^12 = 9.07x10^18

9.07x10^18/6 = 1510956318082499242.6666667

.666667 * 6 = 4

(38^12) mod 3

38^12 = 9.07x10^18

9.07x10^18/3 = 3021912636164998485.333333

.3333333 * 3 = 1

Answer from: Quest

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

Answer from: Quest

answer: b.

step-by-step explanation:

the y coordinate for point b is 0, and answer b is the only one with that y coordinate.

Asap this is a quiz and i cannot redo it

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Compute the value of the following expressions: 323 mod 5 323 div 5 −323 mod 5 −323 div 5 327 mod 3...

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