Hello! i need some figuring out the following parts of trigonometry. since this is a rather difficult math term to understand, i gave out 50 points. : d
bubble in the correct answer choices that go with the correct sentences.
the ratio of the side opposite from an acute angle and the hypotenuse. opposite/hypotenuse
a) trigonometric ratio
b) tangent
c) sine
d) degree
e) cosine
the ratio of the side adjacent an acute angle and the hypotenuse. adjacent/hypotenuse
a) trigonometric ratio
b) tangent
c) sine
d) degree
e) cosine
the ratio of the side opposite from an acute angle and the side adjacent to an acute angle. opposite/adjacent
a) trigonometric ratio
b) tangent
c) sine
d) degree
e) cosine
explain your answers clearly, . will pick brainliest answer!
you!

Alright so these ratios have many different forms but the way I use to remember the trigonometric ratios is:
SOH
CAH
TOA

This means:
Sine --> Opposite/Hypotenuse
Cosine --> Adjacent/Hypotenuse
Tangent --> Oppositie/Adjacent

With that in mind, number 1:
Would be Sine, or C.

Number 2 would be, Cosine, or E.

And number 3 would be Tangent, or B.

Hope that was helpful. 

Solutions 

Trigonometry is the measuring of angles and sides of triangles. In a triangle, there are six elements: 3 sides and 3 angles. A triangle had an Adjacent which is an adjacent next to the angle θ. An Opposite is the opposite the angle θ and the longest side which is the Hypotenuse.

Sine Function: sin(θ) = Opposite / Hypotenuse

Cosine Function: cos(θ) = Adjacent / Hypotenuse

Tangent Function: tan(θ) = Opposite / Adjacent

Answers

Number 1 = (C) 

Number 2 = (E)

 Number 3 = (B)

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12

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