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Mathematics, 02.12.2019 14:31 Sariyahhall1

Calculus 2
if we have
∫ (sec² b / tan² b) sec b tan b db
and u = secb
du = secbtanbdb
and we get ∫(u^2)/(u^2-1) du
how do we go from there to :
∫ ( 1 + (1/(u^2-1) du
can somebody explain to me fully why it became that last expression?

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Answers: 3

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Calculus 2
if we have
∫ (sec² b / tan² b) sec b tan b db
and u = secb
du =...
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