If sin a = 0.31, cos a = 0.95, sin b = 0.47, and cos b 0.88, what is sin(a+b)?

option B

0.72

Step-by-step explanation:

Given in the question,

sin A = 0.31

cos A = 0.95

sin B = 0.47

cos B = 0.88

To solve sin(A+B) we will use trigonometry identities

Compound-angle formulae

Plug values in above formula

(0.31) (0.88)+ (0.95) (0.47)

0.2728 + 0.4465

0.7193

≈ 0.72

0.72

Step-by-step explanation:

Use the sum formula for the sine function:

sin (A + B) = sin A cos B + cos A sin B

Insert the givens into the above formula:

sin (A + B) = (0.31)(0.88) + (0.95)(0.47)

                 =  0.7193, or approx 0.72

3 is greater then both of those numbers