(8q+5)^2=64q^2+[]q+25
what is the missing value? []

  80

Step-by-step explanation:

The square of a binomial is ...

  (a +b)^2 = a^2 + 2ab + b^2

You have a=8q, b=5, so the square is ...

  (8q)^2 + 2(8q)(5) + (5)^2

  = 64q^2 +80q +25

The coefficient missing from your given expression is 80.

3x + 4y -25 =0 represents the amount of change sianna should recieve

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204