If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation h = -16t^2+vt+s, where h is in feet. if the object is propelled from a height of 12 feet with an initial velocity of 64 feet per second, it's height h is given by the equation h = -16t^2+64t+12. after how many seconds is the height 72 feet?

The object first reaches 72 feet after 1.5 seconds; it is this height again after 2.5 seconds.

Step-by-step explanation:

To find the amount of time it takes to reach 72 feet, we solve the equation

72 = -16t² + 64t + 12

To solve this, we will set it equal to 0 by subtracting 72 from each side:

72-72 = -16t² + 64t + 12 - 72

0 = -16t² + 64t - 60

Next we will use the quadratic formula to solve this:

1760 kilometers

step-by-step explanation:

multiply the amount of time the plane took to travel by it's speed

part a

x     y

0     8

1     7.5

2     7

3     6.5

4     6

5     5.5  

for every hour i deducted .5 inches from the length of the candle

part b

it is a function because for every x value there is only one y value

part   c

for every x value there is only one y value

x       y

0       8

1       7.6

2       7.2

3       6.8

step-by-step explanation: