Two containers designed to hold water are side by side, both in the shape of a cylinder. container a has a radius of 13 feet and a height of 13 feet. container b has a radius of 9 feet and a height of 14 feet. container a is full of water and the water is pumped into container b until conainter b is completely full.

to the nearest tenth, what is the percent of container a that is full after the pumping is complete?

The percentage ≅ 48.4%

Step-by-step explanation:

* Lets revise how to find the volume of a container shaped cylinder

- The volume of any container = area of its base × its height

- The base of the cylinder is a circle, area circle = 2 π r,

  where r is the length of its radius

* In container A:

∵ r = 13 feet  , height = 13 feet

∴ Its volume = π (13)² × (13) = 2197π feet³

* In container B:

∵ r = 9 feet  , height = 14 feet

∴ Its volume = π (9)² × (14) = 1134π feet³

* So to fill container B from container A, you will take from

  container A a volume of 1134π feet³

- The volume of water left in container A = 2197π - 1134π = 1063π feet³

* To find the percentage of the water that is full after pumping

  is complete, divide the volume of water left in container A

  by the original volume of the container multiplied by 100

∴ The percentage = (1063π/2197π) × 100 = 48.3841 ≅ 48.4%

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

answer:

3 bags of apples and 2 bags of oranges.

step-by-step explanation: