Answer this multiple choice question!

Explanation:

Triangle PQC is congruent to triangle RQC. We can prove this through use of the hypotenuse leg theorem (HL theorem). Note that PC = RC are congruent radii, and also note that CQ = CQ through the reflexive theorem. We have a pair of hypotenuses and a pair of legs for the right triangles.

Then through CPCTC (corresponding parts of congruent triangles are congruent), we know that the pieces PQ and QR are congruent. For now, let's just call them x. They must add to PR which is 12, so,

PQ + QR = PR segment addition postulate

x + x = 12

2x = 12

x = 6 divide both sides by 2

QR = 6

This shows that if you have a radius perpendicular to a chord of a circle, then the radius will bisect this chord. Bisect means to cut in half.

Step-by-step

There is a theorem in geometry that states that a perpendicular (CQ) to any chord (PR) bisects the chord.  This means that PQ=RQ=6cm.

2.83941151 would be the answer you're looking for! : )