Point a(-7, -2) is rotated 270° counterclockwise and then shifted down 3 units. what are to coordinates of k’?

a. (2,4)

b. (-2, -7)

c. (-2, 4)

d. (7, -5)

C. (-2, 4)

Step-by-step explanation:

First we are going to rotate the point 270°; then we are going to shift it down 3 units.

Remember that the rule to rotate a point 270° counterclockwise about the origin is:

In other words, we just need to switch the coordinates and change the sign of the second coordinate. Let's apply the rule to our point:

Now we know that the coordinates of our point after the rotation are A' = (-2, 7)

The only thing left is shift that point 3 units down; to do it, we just need to subtract 3 from the y-coordinate:

We can conclude that after a rotation of 270° and a translation 3 units down, the coordinates of point K' are (-2, 4).

2.83941151 would be the answer you're looking for! : )

answer: there are 453.592 grams in a pound.