Logan is getting a second dog and wants to increase the length of the play space by 3 feet and the width by 3 feet. what will be the difference in the area, in square feet, between the original play space and the new play space?

Step-by-step explanation:

Let

x------> the length of the original play space

y-----> the width of the original play space

we know that

The area of the original play space is equal to

The area of the new play space is equal to

Find the difference

find the vertical and horizontal asymptotes of the function f x = 5 x − 1 . to find the vertical asymptote, equate the denominator to zero and solve for . since the degree of the polynomial in the numerator is less than that of the denominator, the horizontal asymptote is .

step-by-step explanation: